math question pls help me!!?

Question

(10 - 7x)^2 = 11

Answer 1

First: find the square root of both sides.

√(10 - 7x)^2 = +/- √11
10 - 7x = +/- √11

Sec: subtract 10 from both sides (when you move a term to the opposite side, always use the opposite sign).

10-10 - 7x = -10 +/- √11
- 7x = -10 +/- √11

Third: isolate "x" - divide both sides by -7.

- 7x/-7 = (-10 +/- √11)/(-7)
x = (-10+/- √11)/(-7)

OR, x = -10/-7+(√11)/(-7)
==> 10/7+(√11)/(-7) & 10/7 - (√11)/(-7)

Answer 2

10-7x = √11
-7x = (√11) -10
x = ((√11)-10)/-7
x = .9547678871

Answer 3

Expand the left side to give 49x^2 -140x + 100 = 11. Subtract 11 from both sides to give 49x^2 - 140x + 89 = 0. You can't factor that mess, so use the quadratic formula to get the two roots.

Answer 4

Oy, vey!
Well...I would take the square root of both sides of the equation. Then I'd subtract ten from the right side, and divide both sides by seven to get what x equals.
So it should look a little something like:
x=((+/- square root of 11)-10)/7
That might be wrong, though. You might have to factor the lefst side and then solve for x...

Answer 5

(10-7x)=*square root of 11
10-7x=*square root of 11
-7x=*square root of 11-10
divide both sides by -7
x=*square root of 11-10 both over -7

Answer 6

(10 - 7x)^2 = 11
10 -7x = +/- sqrt(11)

10 -7x = sqrt(11) ----> x = (10 -sqrt(11) )/7

10 -7x = -sqrt(11) -----> x = (10 +sqrt(11) )/7

Answer 7

1: Distribute 2 into ().
2: subt. 10 from both sides.
3: divide by 7.
4. Solve for X.

Answer 8

Multiply first
100-140x+49x^2 = 11
Set = 0
49x^2 -140x +89=0
This doesn't look factorable so now you would use the Quadratic formula

Answer 9

(10-7x)(10-7x)=11
100-140x+49x^2=11
umm then i dont know . . . .
hold on: ugh sry
then you need the perfect square and then solve, i think their shoudl be two answers

Answer 10

i cant write in on the computer but its negative ten plus or minus the square root of eleven all over negative seven