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The quotient of two numbers is four and their diferance is forty nine. What is the smaller number of the two?

2007-11-24 10:31:36 · 4 answers · asked by GF 1 in Science & Mathematics Mathematics

4 answers

Let, smaller one = s and larger one = l.
l/s = 4
or l = 4s _____(1)
l - s = 49 _____(2)

Substituting l from (1) in (2)
4s - s = 49
or s = 49/3
l = 196/3

The smaller no. is 49/3

2007-11-24 10:37:23 · answer #1 · answered by psbhowmick 6 · 0 0

Suppose the smaller number is 'x':

(x+49) / x = 4

Open brackets:

Multiply both sides by x:

x+49 = 4x

Subtract x from both sides:

49 = 3x

x = 49/3

2007-11-24 18:37:19 · answer #2 · answered by Anonymous · 0 0

Let x be the smaller number.
Let y be the larger number.

y = 4x (We know this from the first part of the sentence.)

y - x = 49

4x - x = 49

3x = 49

x = 16.333 (16 and 1/3)

2007-11-24 18:37:54 · answer #3 · answered by lhvinny 7 · 0 0

x/y = 4
Multiply by y and get x = 4y
x - y = 49
Plug in 4y for x
4y - y = 49
3y = 49
y = 49/3
x = 196/3

2007-11-24 18:38:03 · answer #4 · answered by I <3 Taylor Alison Swift 4 · 0 0

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