2007-11-24 10:05:31 · 5 answers · asked by Awan 2 in Education & Reference ➔ Homework Help
yes yes
2007-11-25 14:30:05 · answer #1 · answered by Im Juzt Meh 2 · 0⤊ 0⤋
-27^ 4/3= 3rdroot of -27=-3^4=-81=1/81
2007-11-24 10:41:49 · answer #2 · answered by Dave aka Spider Monkey 7 · 0⤊ 1⤋
(-27)^(-4/3)
the minus in the exponent mean you flip it over
(1/-27)^4/3
the 1/3 inthe exponent means a cube root.
(1/-3)^4
now 1*1*1*1/-3*-3*-3*-3
=1/+81
2007-11-24 10:11:45 · answer #3 · answered by a c 7 · 0⤊ 1⤋
(-27)^(-4/3) = (-1)^(-4/3) {27^(-4/3)}
27 = 3^3;
(-1)^(-4/3) {27^(-4/3)} = (-1)^(-4/3) { (3^3)^(-4/3)} = (-1)^(-4/3) { 3^(-4)} = (-1)^(-4/3) / 81
now let's find (-1)^(-4/3)
-1 = e^(i Ï ) = cos(Ï ) + i sin(Ï ) = -1
(-1)^(-4/3) = (e^(i Ï ) )^(-4/3) = e^(-i4Ï/3)=
cos(4Ï/3) +i sin(4Ï/3) = -0.5(1 - i â3)
hence (-27)^(-4/3) = -0.5(1 - i â3) /81
= -0.00617 +0.01069 i
Summary:
(-27)^(-4/3) = -0.00617 +0.01069 i
2007-11-24 10:32:46 · answer #4 · answered by Any day 6 · 0⤊ 0⤋
yes
2007-11-25 14:26:12 · answer #5 · answered by yalikemystyle4me 1 · 0⤊ 0⤋