simplifying rational expressions?

Question

write the rational expression in lowest terms

3q²-4qz+z²
---------------
q²-2qz+z²

Answer 1

= (3q - z) (q - z) / (q - z) (q - z)
= (3q - z) / (q - z)

Answer 2

factorise the numerator and denominator then cancel any common terms.

3q^2 -4qz + z^2 = (z - 3q)(z - q)
q^2 - 2qz +z^2 = (z -q)(z - q)

so expression (after cancelling) = (z - 3q) / (z - q)

Be carefull of the earlier answers !!

Answer 3

for x^2-12x+35 locate 2 numbers which the multiply is 35 and sum is -12 so we've -7 & -5 for x^2-3x-28 ind 2 numbers which the multply is -28 and sum is -3 so we've 4 & -7 (x-7)(x-5) -------------- (x-7)(x+4) so (x-7) will cancel the we may be able to have (x-5) --------- (x-4)

Answer 4

3q^2-4qz+z^2 = (3q-z)(q-z)
q^2-2qz+z^2 = (q-z)(q-z)

(3q-z)(q-z)
-------------------
(q-z)(q-z)

you can cancel a q-z from the top and bottom and get

3q-z
--------
q-z

Answer 5

anyone who can help me to simplify this one?
1. 3ax + 4by - 2ay - 6bx / 2ax - 2by + ay - 4bx
2. 4x^2 - 12xy + 9y^2 - 16z^2 / 2x^2z - 3xyz + 4xz^2

thanks a lot!

Answer 6

(3q-z)(q-z)/(q-z)^2
=(3q-z)/(q-z)

Answer 7

qz(3q-4+z)
------------
qz(-2+z)

=3q-4+z
-----------
-2+z

=3q-4
----------
-2