factor completely.
5a^2-125
2007-11-24 07:58:32 · 5 answers · asked by God Bless America!~ 4 in Science & Mathematics ➔ Mathematics
5(a^2-25)
=5(a+5)(a-5)
2007-11-24 08:01:26 · answer #1 · answered by norman 7 · 0⤊ 0⤋
Simplifying
5a^2 + -125
Reorder the terms:
-125 + 5a^2
Factor out the Greatest Common Factor (GCF), '5'.
5(-25 + a^2)
Factor a difference between two squares.
5((5 + a)(-5 + a))
Final result:
5(5 + a)(-5 + a)
2007-11-24 16:20:11 · answer #2 · answered by Anonymous · 0⤊ 0⤋
5a^2 -- 125
= 5(a^2 -- 25)
= 5(a + 5)(a -- 5)
2007-11-24 16:02:10 · answer #3 · answered by sv 7 · 0⤊ 0⤋
always check for a GCF first and in this problem both terms are divisible by 5. Factoring out a 5 you get
5(a^2 - 25) now, the binomial is the difference of perfect squares
5(a + 5)(a - 5)
2007-11-24 16:02:02 · answer #4 · answered by Linda K 5 · 0⤊ 0⤋
(5)(a^2 - 25)
(5)(a+5)(a-5)
2007-11-24 16:01:46 · answer #5 · answered by DCPete27 3 · 0⤊ 0⤋