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Two painters are standing on a 5.0 mg long scaffold. Each painter weighs 833 N. 1 painter is standing 2.0 mg from the left end and 1 is standing .50 mg from the right end. The scaffold weighs 285 N. What is the tension in the 2 cables supporting the scaffold?

2007-11-24 07:02:47 · 1 answers · asked by kaynaptx 1 in Science & Mathematics Physics

1 answers

Summing torques at the left cable

T2*5-833*2-285*2.5-833*4.5=0
T2=1225 N

Summing torques at the right cable
T1*5-833*3-285*2.5-833*.5=0
T1=726 N

Check
833*2+285-(1225+726)=0
It checks

j

2007-11-25 08:38:03 · answer #1 · answered by odu83 7 · 0 0

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