2007-11-24 05:23:08 · 10 answers · asked by Boogie 2 in Science & Mathematics ➔ Mathematics
7w (4w² - 9) = 28w³ - 63w
2007-11-28 03:15:56 · answer #1 · answered by Como 7 · 1⤊ 1⤋
The answer
28w^3-63w
2007-11-24 05:49:17 · answer #2 · answered by Anonymous · 0⤊ 0⤋
2w-3)(2w+3 is a difference of 2 squares = 4w^2 -9
7w( 4w^2 -9)= 28w^3 -63w
2007-11-24 05:26:25 · answer #3 · answered by a c 7 · 2⤊ 1⤋
7w(2w-3)(2w+3)
7w(4w^2 -9)
28w^3-63w.
2007-11-24 05:50:49 · answer #4 · answered by Sasi Kumar 4 · 0⤊ 0⤋
-Compare (2w-3)(2w+3) with (a-b)(a+b).
(a-b)(a+b)=a^2 - b^2
Here,a=2w and b=3.
Now,
a^2 - b^2
=(2w)^2 - (3)^2
=4w^2 - 9
Now,
7w(2w-3)(2w+3)
=7w[4w^2 - 9]
=(7w*4w^2) - (7w*9)
=7*4*w*w^2] - 7*9*w
=28*w^3 - 63*w
2007-11-24 05:37:53 · answer #5 · answered by namrata00nimisha00 4 · 2⤊ 0⤋
7w (2w - 3) (2w + 3)
7w (4w^2 +6w - 6w - 9)
7w (4w^2 - 9)
28w^3 - 63w
2007-11-24 05:26:58 · answer #6 · answered by battleship potemkin AM 6 · 2⤊ 0⤋
7w(2w-3)(2w+3)
first you distribute to get:
14w-21w*14w+21w
now combine you like terms on both sides of the equation
-7w*35w
now multiply to get your answer which i got to be
-245w
2007-11-24 05:37:57 · answer #7 · answered by Anonymous · 0⤊ 0⤋
7w(4w^2 - 9)= 28w^3 - 63w
2007-11-24 05:27:03 · answer #8 · answered by mm 2 · 0⤊ 0⤋
(2w-3)(2w+3)=4w^2-9
7w(4w^2-9)=28w^3-63w
2007-11-24 05:54:18 · answer #9 · answered by sarvenaz t 1 · 0⤊ 0⤋
7w(2w-3)(2w+3)
(2w-3)(2w+3)
(2w*2w)+(2w*3)+(-3*2w)(-3*3)
4w^2+6w+(-6w)-9
(4w^2-9)
7w(4w^2-9)
(7w*4w^2)+(7w*-9)
28w^3-63w
2007-11-24 05:32:51 · answer #10 · answered by vi3t10nisgirl 4 · 0⤊ 0⤋