2007-11-24 04:33:46 · 8 answers · asked by Boogie 2 in Science & Mathematics ➔ Mathematics
f ( - 3 ) = 9 + 15 + 6
f ( - 3 ) = 30
2007-11-28 03:32:03 · answer #1 · answered by Como 7 · 1⤊ 1⤋
When x= -2
f( -2)= 4 +10 +6=20.
When x= -3
f( -3)= 9 +15 +6= 30.
2007-11-24 05:59:08 · answer #2 · answered by Sasi Kumar 4 · 0⤊ 0⤋
If your function equals zero, then x can have the value of 2 or 3 since (x - 2)(x - 3) = 0 and setting x - 2 = 0, solving for x; and letting x - 3 = 0 and solving again for x.
2007-11-24 04:38:52 · answer #3 · answered by duffy 4 · 0⤊ 0⤋
f(x) = (-2)^2 - 5(-2) + 6
= 4 + 10 + 6
f(x) = 20
f(x) = (-3)^2 - 5(-3) +6
= 9 + 15 + 6
f(x) = 30
2007-11-24 04:39:54 · answer #4 · answered by Anonymous · 1⤊ 0⤋
x^2 - 5x + 6 = 0
(x - 3) * (x - 2) = 0
x=3, x=2
2007-11-24 04:48:23 · answer #5 · answered by mm 2 · 0⤊ 0⤋
f(x)=x^2-5x+6
f(-2)=4+10+6=20
f(-3)=9+15+6=30
f(2)=4-10+6=0
f(3)=9-15+6=0
2007-11-24 04:44:56 · answer #6 · answered by Anonymous · 0⤊ 0⤋
plug in:
f (-2)=(-2)²-5(-2)+6
f(-2) = 4 +10 + 6
f(-2) = 20
f(-3) = (-3)²-5(-3)+6
f(-3) = 9 + 15 + 6
f(-3) = 30
2007-11-24 04:38:47 · answer #7 · answered by sayamiam 6 · 2⤊ 0⤋
f(-2)=4-(-10)+6=20
f(-3)=9-(-15)+6=30
2007-11-24 04:38:45 · answer #8 · answered by Gabi ng Lagim 7 · 2⤊ 0⤋