Divide
(2x-6)/(21) divided by (5x-15)/(12)
2007-11-24 04:23:26 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
division is the same as multiplying by the reciprocal:
(2x-6)/21 *(12)/(5x-15)
(2x-6)*(12)/21(5x-15)
24(x-3)/ 105(x-3)
notice the x-3 in both numerator and denominator:
24/105
3(8)/3(35)
= 8/35
2007-11-24 04:35:03 · answer #1 · answered by sayamiam 6 · 0⤊ 0⤋
just switch the bottom and then multiply it by the top
(2x-6)/22 * 12/(5x-15)
you can factor some of it...2 goes into both 22 and 12
2(x-3)/11 * 6/5(x-3)
the x-3 cancels itself out on both sides
2/11*6/5
==12/55
2007-11-24 04:33:22 · answer #2 · answered by Briana L 4 · 0⤊ 2⤋
=2(x-3)/21 * 12/5(x-3)
=2 * 12 / (21 * 5)
=8/35
2007-11-24 04:32:50 · answer #3 · answered by norman 7 · 1⤊ 0⤋
Division by a fraction= multiply by reciprocal.
2x-6 * 12
OVER
21 * (5x-15)
EQUALS
24(x-3)
OVER
105(x-3) <<<< just factoring ....
=24/105 << because the (x-3)s cancel each other out.
The answer is 24/105
2007-11-24 04:31:54 · answer #4 · answered by SaintPretz59 4 · 0⤊ 2⤋
Invert the second term and multiply it by the first term (a/b divided by c/d is equivalent to a/b X d/c).
2007-11-24 04:31:56 · answer #5 · answered by williamh772 5 · 0⤊ 1⤋