Divide
(70x^3+35x^2)/(7x)
2007-11-24 04:21:40 · 9 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Divide each term on top separately:
70x^3/7x= 70/7(x^3/x)
70/7=10
x^3/x=x^2
=10x^2.
Now the second term
35x^2/7x=35/7(x^2/x)
35/7=5
x^2/x=x
=5x. Now just add back together
10x^2+5x. The common term here in both parts is a 5x, so you take it out and get
5x(2x+1)
2007-11-24 04:26:45 · answer #1 · answered by Mother Pucker 3 · 1⤊ 0⤋
(70x^3+35x^2)/(7x)
70x^3/7x + 35x^2/7x
10x^2 + 5x
5x(2x + 1)
2007-11-24 04:26:45 · answer #2 · answered by Anonymous · 1⤊ 0⤋
(70x³+35x²) ÷ (7x) = ?
=7(10x³+5x²) ÷ 7(x)
= (10x³ + 5x²) ÷ (x)
= 10x² + 5x
= 5 (2x² + x)
2007-11-24 04:35:40 · answer #3 · answered by rene c 4 · 1⤊ 0⤋
70x^3+35x^2 (10x^3+5x^2)/x = ( 5x^2(2x+1))/x = 5x(2x+1)
------------------=
7x
Divide by 7 Factor 5x^2 divide 5x^2
-everything on top by x= 5x
- to get this
Final Answer is 5x(2x+1)
2007-11-24 04:34:34 · answer #4 · answered by abcd 2 · 1⤊ 0⤋
tsktsk element the equation -5x^4 + 70x^3 - 225x^2 thoroughly. teach your answer. (ouch) -5x^4 + 70x^3 - 225x^2 a million. element the equation by distributive resources, we've: = -5x^2 ( x^2 - 14x + 40 5) {how?} ====>get the finest suitable effortless element (GCF) of the equation, like this: -5x^4 + 70x^3 - 225x^2 x^2 | -5x^2 + 14x - 225 -5 | x^2 - 14x + 40 5 the technique above is like branch, the dividend is on the quotient and the divisor is on the left area. to carry close the GCF of the equation, multiply the to words, (yet some are above 2) of the left area, like this: x^2 mutiplied by -5 is -5x^2. 2. now, element ( x^2 - 14x + 40 5) from the equation, -5x^2 ( x^2 - 14x + 40 5), by element it by factoring trinomial (the alternative of FOIL technique), we've: (x - 9)(x - 5). {how?} easy, on the stated trinomial, be conscious the basically top time period +40 5. attempt to imagine 2 numbers even as they multipied, the answer is +40 5, or perhaps as their sum is the middle time period of the trinomial, it truly is -14. +40 5 = -5 x -9, also -5 + -9 = -14, it truly is the middle time period of the trinomial. fill both element to this, (x + __ )(x + __ ) into (x - 9)(x - 5). the signal could note of regardless of the reality that. to finish the answer, we've = -5x^2 (x - 9)(x - 5)
2016-10-25 00:01:50 · answer #5 · answered by loewus 3 · 0⤊ 0⤋
(70x³ + 35 x²)/7x = 10 x² + 5x
2007-11-24 04:26:15 · answer #6 · answered by ernanepl 3 · 0⤊ 1⤋
10x^2 + 5x
7x|70x^3 + 35x^2
70x^3
--------
0 + 35x^2
35x^2
-------
0
10x^2 + 5x
2007-11-24 04:27:00 · answer #7 · answered by none 2 · 0⤊ 1⤋
(70x^3+35x^2)/(7x)
= [ 7x (10x^2 + 5x)] / 7x........7x's cancel
= 10x^2 + 5x
QED
2007-11-24 04:25:21 · answer #8 · answered by harry m 6 · 0⤊ 1⤋
factor the numerator:
7x(10x^2 + 5)
--------- --------- =
7x
the 7x cancels from the numerator and denominator, leaving:
(10x^2 + 5)
2007-11-24 04:36:40 · answer #9 · answered by sayamiam 6 · 0⤊ 0⤋