2007-11-24 03:59:55 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
[05]
1-sin x cos x tan x
=1-sin x*cos x * sin x/cos x
=1-sin^2 x
=cos^2 x(Proved)
2007-11-24 04:07:49 · answer #1 · answered by alpha 7 · 2⤊ 0⤋
1-sinxcosxtanx
1-sinxcosx(sinx/cosx)
1-sinx(sinx)
1-(sin^2x)
cos^2x
2007-11-24 04:08:15 · answer #2 · answered by GLANY 2 · 0⤊ 0⤋
1 - sin^2 x = cos^2 x
1 - sin x cos x tan x = 1 - sin x * sin x * cos x * sec x
1 - sin x * sin x * cos x * sec x = 1 - sin^2 x
1 - sin^2 x = cos^2 x
2007-11-24 04:05:49 · answer #3 · answered by UnknownD 6 · 1⤊ 1⤋
1 - sin*cos*tan
tan = sin/cos
1 - sin*cos*sin/cos
the cosine's cancel:
1- sin*sin
sin*sin = sin^2
1-sin^2
sin^2 + cos^2 = 1
cos^2 = 1- sin^2
2007-11-24 04:20:48 · answer #4 · answered by sayamiam 6 · 0⤊ 1⤋
1-sinxcosxtanx
=1-sinxcosx(sinx/cosx)
=1-(sinx)^2=(cosx)^2
2007-11-24 04:23:55 · answer #5 · answered by kami 5 · 0⤊ 1⤋
LHS
1 - sin x cos x (sin x / cos x)
1 - sin ² x
cos ² x
RHS
cos ² x
LHS = RHS
2007-11-24 07:18:26 · answer #6 · answered by Como 7 · 4⤊ 1⤋