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Any idea??

2007-11-24 03:16:43 · 4 answers · asked by sabrina 3 in Science & Mathematics Physics

4 answers

They travel at the speed of light.
They are transverse, which means that they vibrate across their direction of travel.
They vary in frequency and wavelength from cosmic and xrays to radio and electric waves.
Speed=frequency X wavelength
light is visible

2007-11-24 03:25:20 · answer #1 · answered by science teacher 7 · 0 0

Electromagnetic waves is energy in the form of transverse waves. It travels through free space at close to the speed of light (186,000 mps). In general electromagnetic waves are set up by electrical and magnetic vibrations that occur universally in atoms. The wavelength of electromagnetic radiation varies inversely with the wave frequency. The waves make up the electromagnetic spectrum, which includes radio waves (including microwaves), infrared waves, , light, ultraviolet radiation, X-rays and gamma radiation.

2007-11-24 11:40:51 · answer #2 · answered by fuck off 5 · 0 0

EM waves, like light, radio, TV, and gamma waves, are waves of particles called photons. They are transverse waves, meaning the waves move up and down perpendicular to the direction of travel...something like the ripples on the surface of a pond cause a floating cork to bob up and down because they are transvers as well. [NB: By comparison, sound waves are compression wave because they oscillate in the direction of travel.]

But unlike the ripples that are perpendicular to just the surface of water, EM waves are oriented 360 degrees around the axis of their direction. We can use something called polarized lenses to block out all but one orientation, which shields us from the harmful rays of the sun when the lenses are our dark glasses. Add one more polarized lens on top of the first one and, orient it just right, and the last remain sun will be totally blocked out.

EM waves are formed of photons, little quanta of energy, much like the ripples on a pond are formed by molecules of water. As energy, each quantum is massless. Each photon has energy E = hf; where h is Planck's constant and f is the frequency of the photon.

From E = mc^2 = hf, we can find mc = hf/c = p, which is a faux momentum for EM photons. It's faux or false because photons do not have mass, but experiments, using photoelectric cells, confirm photons do have momentum p = hf/c even so. That has been somewhat a paradox yet to be resolved.

EM waves travel at the same speed for a given medium when left alone. When the waves are light waves, we call that speed, the speed of light, which is usually connoted as c. So, using the good old distance L = velocity c X time t traveled, we can write L = ct.

If L = ct is the length of a wave (i.e., the wavelength), then L/c = t is called the period. Its units are usually seconds/cycle. And 1/t = f is called the frequency of that wave and its units are typically cycles/second.

So we can write L/t = Lf = c, which shows [this is important] that as frequency goes up, the wavelength has to shorten to keep c constant. And this is true of all EM waves, no matter what medium they are in.

So there you have it. EM travels in transverse waves of photons and wave fronts moving at the speed of light c. The energy of each photon is E = hf, and Lf = c means the wavelength must shorten for increasing frequency (and vice versa). Finally, p = hf/c is a faux momentum EM photons have, but we are not quite clear on why since photons are massless.

2007-11-24 12:12:55 · answer #3 · answered by oldprof 7 · 0 0

they are all transverse
they travel at the speed of light
they can travel through a vaccume
note: sound is NOT part of the electromagnetic spectrum.
the higher the frequency, the shorter the wavelength, the more dangerous the waves are.
speed = frequency x wavelength

check out wikipedia if u want any more info

2007-11-24 12:18:27 · answer #4 · answered by Anonymous · 0 0

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