help pls... anyone?
2007-11-24 02:03:28 · 3 answers · asked by Kris Pogi C 1 in Science & Mathematics ➔ Mathematics
Let bases be a cm and b cm
Altitude = 2 cm
36 = (1/2) (a + b) (2)
36 = a + b
36 = a + (5/4)a
36 = (9/4)a
a = 16
b = 20
Bases are 16 cm and 20 cm
2007-11-27 22:05:55 · answer #1 · answered by Como 7 · 0⤊ 0⤋
let x = standard unit of length of base
A(trap) = (B1 + B2) / 2 * h
.36 = (4x + 5x) / 2 * 2
.36 = 4x + 5x
.36 = 9x
.04 = x
The bases are 16 and 20 cm long
2007-11-24 02:48:26 · answer #2 · answered by jimbob 6 · 0⤊ 0⤋
2m = 200cm
(1/2)(b1 + b2) * (200cm) = 36cm^2
(1/2)(b1 + b2) = (9/50) cm
(b1 + b2) = (9/25) cm
b1:b2 = 4:5
5b1 = 4b2
b2 = 5(b1)/4
9(b1)/4 = (9/25)cm
(b1)/4 = cm/25
b1 = (4/25)cm
b2 = (1/5)cm
2007-11-24 02:20:28 · answer #3 · answered by MathDude356 3 · 0⤊ 0⤋