2007-11-23 20:14:29 · 12 answers · asked by Sidney Shane D 1 in Science & Mathematics ➔ Mathematics
16 you have ten tenths in the one.10/10 plus if you change the 3/5 to tenths that equals 6/10
so you have 10/10 +6/10=16/10 = 1 3/5 . get it. you double the top number. (numerator) and double the bottem number (demominator)) the fraction stays the same such as 1/2 = 2/4=4/8 it is all equal. so you change the 3/5 to 6/10
then 6/10 + 10/10 =16/10
2007-11-23 20:26:35 · answer #1 · answered by hifi1863 2 · 0⤊ 0⤋
1 3/5 = 8/5 = 16/10
2007-11-23 23:24:41 · answer #2 · answered by Nevergiveup_boy 2 · 0⤊ 0⤋
1 3/5 = 10/10 + 6/10 = 16/10 = 16 tenths
2007-11-23 20:59:09 · answer #3 · answered by sv 7 · 0⤊ 0⤋
1 3/5 = 8/5
one tenths = 1/10
Number of 1/10 in 8/5 = (8/5) / (1/10) = (8/5)x(10/1)= 16
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2007-11-23 21:39:44 · answer #4 · answered by Joymash 6 · 0⤊ 0⤋
1 3/5 = 8/5 x 2/2 = 16/10.
2007-11-23 20:18:13 · answer #5 · answered by Beau 6 · 2⤊ 1⤋
1 3/5 = 8/5 = 16/10
16 tenths
2007-11-23 20:23:14 · answer #6 · answered by Como 7 · 0⤊ 2⤋
nicely, you're real. You first want the line perpendicular to y = -3x - 2 that runs interior the direction of the factor (3,a million) m = a million/3 and (3,a million) y - a million = (a million/3)(x - 3) y = (a million/3)x Now, discover the place those 2 strains intersect. y = y (a million/3)x = -3x - 2 2 = (-10/3)x -3/5 = x (-3/5, -a million/5) Now, use the area formulation :: d = ( (x2 - x1)^2 + (y2 - y1)^2 )^(a million/2) d = ( (3 + 3/5)^2 + (a million + a million/5)^2 )^(a million/2) d = ( (18/5)^2 + (6/5)^2 )^(a million/2) d = ( 360 )^(a million/2) / 5 = 3.7947 instruments
2016-12-16 17:17:38 · answer #7 · answered by russ 4 · 0⤊ 0⤋
1 3/5= making 10 the denominator by multiplying 2 and whatever you did to the denominator you mst do to the numerator
1 3/5 * 2/2= 1 6/10
2007-11-24 02:40:51 · answer #8 · answered by Dave aka Spider Monkey 7 · 0⤊ 0⤋
16/10
2007-11-24 02:59:27 · answer #9 · answered by jimbob 6 · 0⤊ 0⤋
1 3/5 = 8/5 = 16/10 = 1.6
i.e. 1.6 tenths
2007-11-23 21:07:54 · answer #10 · answered by Shrikant R 2 · 0⤊ 0⤋