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"A beaker of water and a brass cylinder are placed side by side on the pan of a balance and weighed (the cylinder is next to the beaker, not in it). The brass cylinder is then placed in the water and it rests on the bottom of the beaker. Does the balance read different in this case? Explain your answer, and show that it is agreement with Newton's 3rd law of motion (equal and opposite forces)."

Thanks for any help!

2007-11-23 19:51:35 · 3 answers · asked by Metallus 1 in Science & Mathematics Physics

3 answers

Of course the balance reads the difference before coming to equilibrium. Just make a graph between Time(of Measurement- scale is probably micro seconds?) and Wieght.

The graph possibly goes Oscillating damping first(Sinusoidal) and then comes to rest. But

2007-11-23 20:13:17 · answer #1 · answered by kay kay 4 · 0 1

If the beaker doesn't overflow, the balance reads the same.

2007-11-24 04:09:26 · answer #2 · answered by Helmut 7 · 0 0

no explanation needed

the amount of material on the weighing pan is unchanged

no chemical reaction, no heat or gasses generated

2007-11-24 06:45:01 · answer #3 · answered by Anonymous · 0 0

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