to get tehe square root do the follwoing
1st divide digits of the number into pairs
for example
if the number is 48596
make is
04 85 96
& start from the left pairs
04 , find out a number its square equals to or just less than 4 ---> it is 2
then subtract this square from the left pairs of number
04 85 96
04
------
00 85 96 ----------> until now the result contains 2
85 96
then the rest we will use the following formula a(a+20 r)
where r is the result the we get from the start till the previous step
& 'a' is an integer number 0 <=a <=9
in this formula a(a+20 r) a must be less than the next pairs (with the remain if any)
so here we need the value of 'a' where a(a+20*2)<= 85
a(a+40)<=85
if a 0--->0 1--->41 2--->84 3----> 129
so it is 2
so put it to the right side of the result (the result will be (22)
subract
85 96
84
--------
01 96
then use the formula again
find a where a(a+20*22)<196
a(a+440)<196
if a 0--->0 1--->441 >196
so a here will be 0
& the reault will be (220)
& the remain is 196
if u want to continue with fraactions
add 00 to the right & a decimal point in the result
so
19600
find a where a(a+20*220)<19600
it will be 4 4(4+4400)= 17616
put 4 in the result (220.4)
subtract
19600
17616
--------
1984
add 00
198400
and so on
----------------------
try to get the square root of 2 with this method
the start is
02 ---->a=1
01
-----(subtract)
01 00 (result 1. )
a(a+20*1)<100 a=4--->96
subtract
1 00
0 96
-----
4 00 ------->result (1.4)
and so on
2007-11-23 18:21:50
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answer #1
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answered by mbdwy 5
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Well Today is your lucky day if you dont want to use the cal use your brain lets start with let x = √2 then square both sides gives us x^2 = 2 right take 2 to the left hand side gives us x^2 -2 = 0 >>> which gives us a graph of y= x^2 -2 ...
Now the tricky part use this FORMULA A - F(a)/F'(a) where your equation is f(a) x^2 -2 .. take a approximation of say 1.8
then do this 1.8 - F(1.8) divided by F'(1.8) remember F'(a) is the dy/dx ok ill just give you the final step so you just need o substute in your calcultor and you got he best approx of V2 ok
1.8 - 1.24/ 3.6 should give you close to 1.4 ive got this another method which is a pattern if you need it pm me on da_w3st_sid3_@hotmail.com but the method i showed you works for all square roots of all numbers thanks
2007-11-23 18:06:55
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answer #2
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answered by Anonymous
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Sense they are both square roots, all you have to do is multiply the numbers and keep t as a square root. Sooooo. Sqrt of 116 Times Sqrt of 2 = sqrt of 232 ( because 116 times 2 = 232) another example... What is the sqrt of 3 times the square root of 5? Well, That is the sqrt of 15... Same with addition, subtraction and multiplication... EXAMLES: sqrt of 5+sqrt of 3+ sqrt of 8 sqrt of 5 - sqrt of 3 = sqrt of 2 sqrt of 10 divided by sqrt of 5 = sqrt of 2 hope I helped! :) -Andrew
2016-03-14 00:49:26
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answer #3
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answered by Anonymous
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Newton's Approximation:
each iteration is more accurate than the last, with n being the argument of the sqrt function
x(k+1) = 0.5*(x(k) + n/x(k)) with x(0) = 1
for example, when n=2, x(0...4)=
1
1.5
1.41667
1.41422
1.41421 ~= sqrt(2)
Without a calculator, just guess and check each decimal place, approximately dividing your remaining range by two if possible:
1^2 = 1 (>)
2^2 = 4 (<)
::1
1.5^2 = 2.25 (<)
::1
1.3^2 = 1.69 (>)
::1.3
1.4^2 = 1.96 (>)
::1.4
...
2007-11-23 18:04:10
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answer #4
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answered by MooseBoys 6
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all you have to do is think of a number that multiplies by itself and the # u get is its square. So the square root of the # is the orginal # you multiplied. Say u use the # 3. 3 * 3 is 9. So the square root of 9 is 3. Not hard.
2007-11-23 18:02:10
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answer #5
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answered by cassie_sweet_16 2
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(radical)2
add a 0 in front of the 2
(radical)02
now theres a pair behind the decimal
so estimate the square root of 02
which is approx. 1.4
think: 1.4 x 1.4 = 1.96 (2)
2007-11-23 18:19:33
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answer #6
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answered by Anonymous
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square root of 2= 1.4141
2007-11-23 18:07:01
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answer #7
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answered by Anonymous
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I don't know about the exact way of doing this, but I know that sqrt(2) has to be a little more than 1 but a little less than sqrt(3) which is less than sqrt(4) = 2, so it should be about 1.4
2007-11-23 18:01:52
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answer #8
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answered by Anonymous
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Someone already mentioned using Newton's Method.
Other ways to approximate it are by using the Secant Method or by using the Taylor Series.
2007-11-23 19:03:26
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answer #9
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answered by Ranto 7
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Then check the site in the source.
2007-11-23 17:57:59
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answer #10
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answered by perplexed* 3
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