2007-11-23 17:51:05 · 8 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
just replace all x's with 2
F(2) = 2(2)^2 - 7(2) + 3
F(2) = 2(4) - 7(2) + 3
F(2) = 8 - 14 + 3
F(2) = -3
2007-11-23 17:55:47 · answer #1 · answered by Dino 3 · 0⤊ 0⤋
F(x)= 2x^2-7x+3
to find f(2), you just replace every x with 2.
f(2) = 2(4) - 7(2) +3
f(2) = -3
2007-11-24 01:59:13 · answer #2 · answered by absentmindednik 3 · 2⤊ 0⤋
2(2)^2-7(2)+3 = f(2)
= 8 -14 +3 = -3
2007-11-24 01:59:16 · answer #3 · answered by Anonymous · 1⤊ 0⤋
â«F(x) dx = f(x)
So you first have to take the integral of F(x).
f(x) = â«2x^2 - 7x + 3 dx
f(x) = (2x^3)/3 - (7x^2)/2 + 3x + C
f(x) = (2/3)(x^3) - (7/2)(x^2) + 3x + C
If you were given an additional point that fits into this equation, you could now solve for C. However, in this case you weren't supplied with one, so I guess you would go ahead and solve for f(2).
f(2) = (2/3)(8) - (7/2)(4) + 3(2) + C
f(2) = (16/3) - 14 + 6 + C
f(2) = (16/3) - 8 + C
f(2) = (-8/3) + C
2007-11-24 02:06:42 · answer #4 · answered by kendall_krazy49 2 · 2⤊ 2⤋
f(2)=-3
2007-11-24 03:11:47 · answer #5 · answered by someone else 7 · 1⤊ 1⤋
if f(x)=x then f(1)=1
so we have to substitute the given value in the place of x
f(x)= 2x^2-7x+3
f(2)=2[(2)^2]-7(2)+3
f(2)=2(4)-14+3
f(2)=8-14+3
f(2)=11-14
f(2)= -3
2007-11-24 01:59:58 · answer #6 · answered by snehalu 3 · 1⤊ 0⤋
plug in 2 for x:
f(2) = 2(2)^2 - 7(2) +3
f(2) = 8 - 14 + 3
f(2) = -3
2007-11-24 02:12:56 · answer #7 · answered by sayamiam 6 · 1⤊ 1⤋
f(2) = 2 (4) - 14 + 3
f(2) = 8 - 11
f(2) = - 3
2007-11-24 05:19:20 · answer #8 · answered by Como 7 · 1⤊ 1⤋