English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

1. C2H4(g) + O3(g) -> CH3CHO(g) + O2
in KJ

2. O3(g) + NO(g)-> NO2 (g) + O2(g)
in KJ

3. SO3(g) + H2O(l) -> H2SO4(aq)
in KJ

4. 2NO(g) + O2(g)-> 2NO2(g)
inKJ

2007-11-23 17:48:55 · 2 answers · asked by Anonymous in Science & Mathematics Chemistry

2 answers

Jenny is right. The elements in their standard states are like "sea level", in my other answer. Remember to score elements in standard state as zero, multiply by number of moles in eq., add up products and subtract reactants.

2007-11-23 23:22:29 · answer #1 · answered by Facts Matter 7 · 0 4

You have to use Hess's Law which says that the ΔH for the reaction is that of the products minus the reactants. you can look up the individual ΔHs from NIST webbook. I'll use #1 as an example.

C2H4(g) + O3(g) -> CH3CHO(g) + O2

C2H4=52.47 kJ/mol
O3= 142.67 kj/mol
CH3CHO=-170.7kJ/mol
O2= 0kJ/mol

(-170.7+ 0) - (52.47+142.67) = 365.84 kJ/mol

2007-11-23 18:29:41 · answer #2 · answered by Jenny 3 · 7 2

fedest.com, questions and answers