multiply
2m(5m-3)(4m+7)
2007-11-23 15:45:32 · 4 answers · asked by crazy4u 1 in Science & Mathematics ➔ Mathematics
(10m^2 -6m)(4m+7) First multiply 2m by 5m-3=10m^2 -6m
("10m^2" -6m)("4m"+7) Then multiply the first terms which is 10m^2 and 4m=40m^3
("10m^2" -6m)(4m "+7") Then multiply the far terms which is 10m^2 and 7= 70m^2
(10m^2 "-6m")("4m" +7) Then multiply the close terms which is -6m and 4m= -24m^2
(10m^2 "-6m")(4m "+7") Then multiply the last terms which is -6m and 7= -42m
It would be 40m^3 [+70m^2 -24m^2] -42m simplified to
70m^3 +46m^2 -42m ~~~Answer
2007-11-23 16:32:49 · answer #1 · answered by Internet Explorer 2 · 0⤊ 0⤋
1. Expand.
(5m-3)(4m+7) = 20m^2 + 35m - 12m-21
= 20m^2 + 23m - 21
2. Multiply
2m(20m^2 + 23m - 21)
=40m^3 + 46m^2 - 42m
2007-11-24 00:15:08 · answer #2 · answered by kodie 5 · 0⤊ 0⤋
= 2m(2m - 3)(4m + 7)
= (4m^2 - 6m)(4m + 7)
= 16m^3 + 28m^2 - 24m^2 - 42m
= 16m^3 + 4m^2 - 42m
2007-11-24 00:13:40 · answer #3 · answered by Jun Agruda 7 · 3⤊ 0⤋
2m(20m^2+23m-21)
=40m^3+46m^2-42m
2007-11-24 00:10:21 · answer #4 · answered by norman 7 · 0⤊ 0⤋