help me please!!!?

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three blocks are attached by cords that loop over frictionless pulleys. Block B lies on a frictionless table; block A hangs to the left side of the table and block C hangs to the right side. the masses are mA = 5.40 kg, mB = 8.00 kg, mC = 14.5 kg. When the blocks are released, what is the tension in the cord at the right?

2007-11-23 15:43:46 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Physics

2 answers

14.5kg

2007-11-23 16:52:45 · answer #1 · answered by Anonymous · 0⤊ 0⤋

a ≈ 9.80665(14.5 - 5.4) / (14.5 + 8.00 + 5.4)
a ≈ 9.80665(9.1) / 27.9
a ≈ 3.198585
T ≈ 14.5(9.80665 - 3.188585)
T ≈ 95.8169 N

2007-11-23 17:09:13 · answer #2 · answered by Helmut 7 · 0⤊ 0⤋