Solve the following system of equations for x:?

Question

4x + y = 11
x + y = 2

Answer 1

[05]
4x+y=11.......(1)
x+y=2...........(2)
From (2),we get y=2-x
substituting y by 2-x in eqn 1,we get
4x+2-x=11
3x=11-2=9
x=9/3=3
plugging x in eqn (2)
3+y=2
y=2-3= -1
x=3 and y= -1 ans

Answer 2

Multiply all the terms in the bottom equation by -1, then add the equations together.

4x + y = 11
-1(x + y) = 2

4x + y = 11
-x - y = -2

3x = 9
x = 3

Since you said you only need to solve for x, this is all you need to do. However, it is quite simple to solve for y at the same time. Simply plug your new x-value into either equation and solve for y

3 + y = 2
y = -1

Answer 3

subtract equations; negate the first equation so times the first equation by -1. we get
-4x -y = -11
x+y = 2
-3x = 9
x = -3 ; so
x+y = 2
-3+Y = 2
y = 5

Answer 4

4x + y = 11
x + y = 2

You want to get the equation so that one of the varibles cancells out so:

4x + y = 11
(-1)*(x + y = 2)

gives you:
4x + y = 11
-x - y = -2

cacelling out the y's leaving you:

4x = 11
-x = -2

this gives you the equation:

3x=9

now divide by 3 on both sides and

x=3

Answer 5

to solve for x, you should find the difference of 4x + y= 11 and x + y= 2

4x- x= 3x
y-y=0
11-2= 9

We 're left with 3x(+0)=9
We get rid of the + 0 so...

3x=9...

We divide both 3x and 9 by three...

x=3

Answer 6

4x+y=11 -- (1)
x+y=2 -- (2)
y=2-x (from (2))
plug into (1)
4x+(2-x)=11
3x+2=11
3x=9
x=3
form (2) y=-1

Answer 7

Use substitution

x=2-y

4(2-y)+y=11
8-4y+y=11
8-3y=11
8-3y=11
8-8-3y=11-8
-3y=3
y=-1

x-1=2
x=3

Answer 8

Dear Laura:

We are not here to do your homework for you... You need to be able to do these yourself. This is not the first question you've asked in the last ten minutes.

Talk to your teacher if you need extra assistance.

Answer 9

subtract eq.2 from eq. 1