(3/x+3)+1=(7/x+3)?

Question

Solve and check

(3/x+3)+1=(7/x+3)

Answer 1

(3/x+3) +1 = (7/x+3)
(3/x+3) + x+3/x+3 = (7/x+3)
(3 + 3 + x) / (x+3) = (7/x+3)
Multibly both sides with x+3
3+3+x = 7
6 + x = 7
x = 7 - 6
x = 1
For checking
(3/1+3)+1=(7/1+3)
(3/4)+1=(7/4)
3/4 + 4/4 = 7/4
7/4 = 7/4
therefor x=1 is a correct answer

Answer 2

sol'n:
(3/x+3) + 1 = (7/x+3), multiply both sides with x+3,
so,
3 + (x+3) = 7
therefore, x=1...

to check if the answer is true,
substitute the value of x in the original equation.

so,

(3/1+3) + 1 = 7/1+3

3/4 + 1 = 7/4
(3/4) + (4/4) = (7/4)
therefore,

(7/4) = (7/4)...Q.E.D.
the value of x = 1

Answer 3

3 + x + 3 = 7
x = 1
Check
3 / 4 + 1 = 7 / 4

Answer 4

3/(x + 3) + 1 = 7/(x + 3)

3 + x + 3 = 7 {multiply both sides by x + 3}
x + 6 = 7
x = 1

Answer 5

Rearrange the equation to the constants on one side and the variables on the other:

1 = 4/x

Then it's simple, just take the inverse of both sides and you get:

x = 4