Find an equation in standard form of the line passing through the points (8, -5) and (-6, 2).?

Answer 1

m = (2 + 5) / (- 6 - 8)
m = 7 / (- 14)
m = (- 1/2)
y - 2 = (-1/2) (x + 6)
y = (-1/2)x - 3 + 2
y = (-1/2)x - 1
Or
2y = - x - 2
x + 2y + 2 = 0

Answer 2

^ but that wouldn't be in standard form. You can, however, use the y=mx+b formula to figure out your standard form equation.

m=(2- -5)/(-6-8)=7/-14=-1/2
2=-1/2(-6)+b
2=3+b
1=b

y=-(1/2)x+1

Now the slope in a standard form equation is the opposite coefficient of x over the coefficient of y, so that side of the equation would look like this:

2y+x

And the y-intercept is the other side of the equation divided by the coefficient of y. Since the coefficient of y is 2, and we know the y-intercept is 1, your standard form equation should look like this:

2y+x=2


y=mx+b is slope-intercept form, ax+by=c is standard form.

Answer 3

It's easiest to calculate the slope first, then use the point-slope equation.

To find slope, take
y2 - y1 / x2-x1
So,
2+5 / -6-8
= 7/-14
or
m=-1/2

Then, use the equation
y-y1 = m(x-x1)
So,
y+5=-1/2(x-8)

And, solve or isolate y by distributing the slope, m [-1/2]

y+5=-1/2x+4

Subtract 5 from both sides.

y=-1/2x-1

Standard form is Ax + By = C
So,
1/2x + y = -1

Answer 4

Step 1 (find the slope)

(x1,y1) = (8,-5)
(x2,y2) = (-6,2)

m = (y2 - y1)/(x2 -x1)

= (2 -(-5))/(-6 - 8)

= 7/-14

= -1/2

Step 2 (find equation) with (x1,y1) = (8,-5)


m = -1/2 (y - y1)/(x - x1)

-1/2 = (y -(-5))/(x - 8)

-1/2 = ( y + 5)/(x - 8)

-x + 8 = 2y + 10

-2y -x -2 = 0 (multiplied both sides by (-1))

2y +x +2 = 0

x + 2y + 2 = 0 (standard form Ax + By + C = 0)

Answer 5

Find the slope first. -5-2 over 8--6

-7/14

y=-1/2 x +b
2= -1/2 *-6 +b
2= 3 +b
-1 = b

y= -1/2 x -1

Answer 6

the formula for the line is
y=mx+b

so take a piece of graph paper and plot those 2 points.
the point where it crosses the y-axis is the "b" in the formula. Then use rise/run to give you the slope (which is "m" in the formula) if you do that step by step you should be able to get the correct answer

Answer 7

(x1,y1)=(8,-5)
(x2,y2)=(-6,2)

formula:

y = mx + c

m,gradient/slope = (y2-y1)/(x2-x1) = (2--5)/(-6-8)=7/-14 = -0.5 or -1/2

to solve c put one of the co-ordinates into the above formula:

-5 = -0.5*8 + c
-5 = -4 + C
C = -1

Therefore the equation is:

y = -0.5x -1