4x^2+2x-3=0?

Question

I am not sure how to do this, if someone could help me with the steps it would mean a lot. Thanks


Solve by completing the square. Express your answer in simplified radical form.


4x^2+2x-3=0

Answer 1

(2x+3)(2x-1)=0

2x+3=0
2x-1=0

2x=-3
2x=1
x=-3/2 or 1/2

Answer 2

since this cannot be factored...use the quadratic formula to solve it (cannot be factored b/c hint= "radical form")

so the formula is

http://media.nasaexplores.com/lessons/01-003/images/quadform.gif
(use photo b/c of the symbols you need)

then just plug in..in your problem:

a=4
b=2
c=-3

Answer 3

roots of eq. aX^2 + bX + c = 0 are

(-b +- sqrt(b^2 - 4ac) )/ 2a

a = 4
b = 2
c = -3

Substitute and have fun...