factor completely
if polnomial cannot be
factored write "prime"
2007-11-23 08:54:03 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
(x² - 9)(x² - 9)
(x - 3)(x + 3)(x - 3)(x + 3)
(x - 3)² (x + 3)²
2007-11-23 09:03:18 · answer #1 · answered by Como 7 · 1⤊ 1⤋
X^4-18x^2+81=(x^2-9)(x^2-9)
=(x-3)(x+3)(x-3)(x+3)
=(x-3)^2(x+3)^2
2007-11-23 17:07:38 · answer #2 · answered by Anonymous · 0⤊ 1⤋
x^4 - 18x^2 + 81
(x^2 - 9)(x^2 - 9)
Difference of two squares x^2 - y^2 = (x + y)(x - y)
(x + 3)(x - 3)(x + 3)(x - 3)
(x + 3)^2(x - 3)^2
2007-11-23 17:01:18 · answer #3 · answered by kindricko 7 · 0⤊ 1⤋
x^4 = (x^2)^2
81 = 9^2
x^4 -18x^2 +81 = (x^2 -9)^2
x^2 - 9 = (x-3)(x+3)
(x^2-9)^2 = [(x+3)(x-3)]^2 = (x+3)^2 (x-3)^2
2007-11-23 16:58:44 · answer #4 · answered by lhvinny 7 · 0⤊ 1⤋
(X^2-9)^2
[(x-3)(x+3)]^2
2007-11-23 17:01:08 · answer #5 · answered by mbdwy 5 · 0⤊ 1⤋
(x^2-9)(x^2-9)
2007-11-23 16:56:53 · answer #6 · answered by topher098321 2 · 1⤊ 1⤋