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(x^2/x-3)-(9/x-3)

2007-11-23 08:42:06 · 2 answers · asked by shawntae6513 1 in Science & Mathematics Mathematics

2 answers

The denominators are the same, so you can simply subtract the numerators to form one fraction.

(x^2-9)/(x-3)

You can then factor the numerator because it is a difference of squares to form a new fraction, which you will be able to get rid of the denominator.

(x+3)(x-3)/(x-3)
x+3

It's important to note though that the domain will still be all reals except 3, because in the original equation you could not have 3 in the denominator. Even though x+3 is defined for all reals, the original equation was not, which is what you are rewriting.

2007-11-23 08:48:22 · answer #1 · answered by topher098321 2 · 0 0

common denominator means we can subtract the numerators.

(x^2 - 9) / (x-3)

x^2 - 9 factors into (x-3)(x+3)

so we have (x+3)(x-3)/(x-3)

The x-3 will cancel each other out.

Final answer is x+3

2007-11-23 08:48:26 · answer #2 · answered by lhvinny 7 · 0 0

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