4x^2 - 4x - 3 < 0?

Answer 1

(2x+1)(2x-3)<0

either
(2x+1)<0 and (2x-3)>0
2x<-1 and 2x> 3
x<-1/2 and x>3/2

which is impossible


OR


(2x+1)>0 and (2x-3)<0
2x>-1 and 2x< 3
x>-1/2 and x<3/2

which means x is between -1/2 and 3/2

-1/2
Pick zero, see, it works.

Answer 2

4x^2 - 4x - 3 < 0?

let it = k

4x^2 - 4x - 3 = k

or 4x^2 -4x - (3+ k) =0

Then test the result for values of K that give < 0

why ask the same question twice
4x^2 - 4x - 3 < 0?
X^2 + 2x - 1 < 0?

Answer 3

-1/2 < x < 3/2

Answer 4

First find the critical pts. (x-intercepts) than do a number line test to see when it's positive and when it's negative.

(2x+1)(2x-3) < 0
4(x+1/2)(x-3/2) < 0

From (-infinity, -1/2) y is positive
From (-1/2,3/2) y is negative
From (3/2,infinity) y is positive

So from (-1/2,3/2) , 4x^2-4x-3 is < 0

Answer 5

solve
4x^2 - 4x - 3 = 0

(2x +1)(2x - 3) = 0

2x + 1 =0 or 2x - 3 = 0

x = -1/2 or x = 3/2

4x^2 - 4x - 3 < 0

=> x < -1/2 or x > 3/2...........u shaped graph

Answer 6

4x^2 - 4x - 3 < 0
(2x +1)(2x - 3) < 0
x < -1/2
x > 3/2

Answer 7

(2x - 3)(2x + 1) < 0

2x - 3 > 0 and 2x + 1 < 0
x > 3/2 and x < - 1/2
not acceptable

OR

2x - 3 < 0 and 2x + 1 > 0
x < 3/2 and x > - 1/2
is acceptable

Answer 8

Assuming you want us to discover the value range for x.....

(2x +1)(2x - 3) < 0

2x + 1 < 0 and/or 2x - 3 < 0

x < -1/2 and/or x < 3/2

Since -1/2 < 3/2, the correct answer is only the first of the two possible answers.

x < -1/2

Answer 9

I'm really rubbish at mathematics. I can spell, add up, multiply, do division and subtract. I can also work out percentages but your question has me completely stumped. Sorry.