Change the first equation to x = 3y + 4, and subst. it into the second:
-3(3y + 4) + 5y = -14
-9y - 12 + 5y = -14
-4y = = -2
y = 1/2
x = 3(1/2) + 4 = 3/2 + 8/2 = 11/2
x= 11/2 and y = 1/2
that's it!
2007-11-23 07:11:35
·
answer #1
·
answered by Marley K 7
·
1⤊
0⤋
Solving by substitution meaning you need to solve one equation for one single variable and then plug what it equals in to the other.
Solve first one for x
x - 3y = 4 , add 3y to both sides
x = 3y + 4 , now that we know that x = 3y + 4 then put it in for x in the second location where ever you see x
-3x + 5y = -14 , make the substitution
-3 (3y +4) + 5y = -14 , distribute the -3
-9y - 12 + 5y = -14 , combine the y's and add 12 to both sides
-4y = -2 or y = 1/2 , then plug 1/2 in for y
x - 3(1/2) = 4 or x - 3/2 = 4
x = 11/2
2007-11-23 15:19:55
·
answer #2
·
answered by ? 3
·
1⤊
0⤋
First, solve for x in the first equation.
x - 3y = 4
x = 4 + 3y
Then substitute 4 + 3y in for x in the second equation and solve for y.
-3x + 5y = -14
-3(4 + 3y) + 5y = -14
-12 + -9y +5y = -14
-12 - 4y = -14
-4y = -2
y = 1/2
Finally, substitute this value for y into one of the original equations, and solve for x.
x - 3(1/2) = 4
x = 11/2
So: x = 11/2 and y = 1/2
2007-11-23 15:13:43
·
answer #3
·
answered by Anonymous
·
0⤊
1⤋
from first equation
x-3y = 4
x = 4 + 3y
put the new value of x in second equation
-3(4+3y) + 5y = -14
-12 - 9y + 5y = -14
-9y + 5y = -14 + 12
-4y = -2
4y = 2
y = 2/4
y= 1/2
put new value of y in first equation
x - 3(1/2) = 4
x - 3/2 = 4
x = 4 + 3/2
x = 8/2 + 3/2
x = 11/2
therefor
x= 11/2 and
y = 1/2
2007-11-24 01:20:17
·
answer #4
·
answered by Rayan Ghazi Ahmed 4
·
0⤊
0⤋
x - 3y = 4 can be written as x = 4+3y by adding 3y to both sides of the equation.
now substitute the x in -3x+5y = -14 with x = 4+3y
you will get -3(4+3y) +5y = -14
at this point you have one equation and one unknown. solve for y then plug that answer into one of the original equations and solve for x. hopefully you can figure out the rest from here.
2007-11-23 15:13:12
·
answer #5
·
answered by risca369 1
·
0⤊
1⤋
1st eqn:
x= 3y+4
-3x + 5y = -14
-3(3y+4) + 5y = -14
-9y - 12 + 5y = -14
-4y = -2
y = 1/2
x = 3y+4
x = 3(1/2) +4
x = 11/2
(11/2,1/2)
2007-11-23 15:10:28
·
answer #6
·
answered by sayamiam 6
·
1⤊
0⤋
x = 3y+4. then substitute 3y+4 into the other equation as x. therefore, -3(3y+4)+5y=-14.
2007-11-23 15:13:28
·
answer #7
·
answered by Anonymous
·
0⤊
0⤋
x-3y=4 , multiply it with 3 = 3x-9y= -12 .............1
-3x +5y= -14......... ....2
Add 1&2 -4y= -26
y= 26/4= 13/2
Sub Value y in 1, x -3*13/2=4, x= 4 +39/2
x= 47/2, y= 13/2.
2007-11-23 15:21:37
·
answer #8
·
answered by Sasi Kumar 4
·
1⤊
0⤋
x=4+3y
-12-9y+5y=-14
-4y = -2 ,,,,y = 1/2 , x=4+3/2,,,x= 8+3 /2 = 11/2
2007-11-23 15:11:13
·
answer #9
·
answered by iceman 7
·
1⤊
1⤋
x = 4 + 3y
- 12 - 9y + 5y = - 14
- 4y = - 2
y = 1/2
x - 3/2 = 4
x = 11/2
x = 11/2 , y = 1/2
2007-11-23 15:11:52
·
answer #10
·
answered by Como 7
·
1⤊
1⤋