2007-11-23 06:39:06 · 6 answers · asked by Alexander 6 in Science & Mathematics ➔ Mathematics
f `(x) = 3x² + 4x + 3 + cos x
f "(x) = 6x + 4 - sin x
f ```(x) = 6 - cos x
f ```` (x) = sin x
2007-11-23 06:43:44 · answer #1 · answered by Como 7 · 4⤊ 1⤋
f(x) = x³ + 2x² + 3x + 4 + sin(x)
f'(x) = 3x² + 4x +3 + (0) + cos (x)
f''(x) = 6x + 4 - sin (x)
f'''(x) = 6 - cos x
f''''(x) = sin x
I think that's right and how did your raise the exponential numbers with your keyboard?
2007-11-23 06:45:24 · answer #2 · answered by Anonymous · 2⤊ 1⤋
f(x)= x³ + 2x² + 3x + 4 + sin(x)
f'(x)=3x²+4x+3+cos(x)
f''(x)=6x+4-sin(x)
f'''(x)=6-cos(x)
f''''(x)=sin(x)
2007-11-23 06:47:07 · answer #3 · answered by 2FastEddie 2 · 2⤊ 0⤋
f''''(x) = sin(X)
Please Mark This Answer As the Best If It was Helpful
2007-11-23 06:44:24 · answer #4 · answered by None 2 · 2⤊ 2⤋
=sin(x)
2007-11-23 06:47:59 · answer #5 · answered by sunny-d alright! 5 · 2⤊ 0⤋
thats hard
2007-11-23 06:41:49 · answer #6 · answered by Anonymous · 1⤊ 2⤋