A contract is to be completed in 46 days and 117 men were set to work, each working 8 hours a day. After 33 da

Question

A contract is to be completed in 46 days and 117 men were set to work, each working 8 hours a day. After 33 days 4/7 of the work is completed. How many additional men may be employed so that the work may be completed in time, each man now working 9 hours a day?

Answer 1

117 men x 8 hours x 33 days = 4/7 of the job
30,888 hours = 4/7 of the job

Set up a ratio:
n hours = 3/7 of the job

30888 ... n
--------- = ----
(4/7) ......(3/7)

n = 30,888 x (3/7) / (4/7) = 30,888 x 3/4
n = 23,166 hours

So now you need to complete 23,166 hours in 14 days at 9 hours a day.

Let m be the number of men.
m x 13 days x 9 hours = 23,166
m = 23,166 / 13 / 9
m = 198

Given that you already have 117 men, you need to add an additional 81 men.

(This all assumes that they work at the same rate as the others have in the past).

Answer 2

117 men work 8 hours/day for 33 days, so that's 117*8*33 = 30888 hours spent on 4/7.

This means 3/7 is 30888/4 *3 = 23166, so 23116 hours that need to be spent in (46-33=13) 13 days, 9 hour/day

x*13*9 = 23116
x = 23116/(13*9) = 198 men needed.

There are already 117, 198-117 = 81 men to hire to complete it in time.

Answer 3

In 33 days 117 men worked 117 x 33 x 8 =30888 hours.
4/7th of the work in 30888 hours
30888 hours for 4/7th of work
so, 54054 hours for the whole work = 30888/(4/7)
Hours of work to be completed = 54054-30888=23166 hours
117+x men , 9 hrs a day, 13 days
(117+x)(9)(13)=23116
13689+117x=23116
117x=9427
x=80.6=87 men ?

Answer 4

do your own home work"