simplify 5 raised to the power of log5 13?

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2007-11-23 00:43:02 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics

the base 5 and the log5 cancels each other out ..
hence the answer is 13

2007-11-23 00:52:17 · answer #1 · answered by pyrodude1031 2 · 0⤊ 0⤋

According to the definition of the log:
If a^b=c, b=log(base a)c

Now, let a be 5 and c be 13:

5^b = 13

b = log5 13

Thus, 5^(log5 13) = 13

2007-11-23 08:58:59 · answer #2 · answered by Amit Y 5 · 0⤊ 0⤋

If a base is raised to a logarithm with the same base; (ex: a^loga x) it is equal to x. hence 5^log5 13 is 13

2007-11-23 09:07:11 · answer #3 · answered by Jeff M 2 · 0⤊ 0⤋

If you are interested in learning logarithm you first learn these.

logM+logN=log(MN)
logM-logN=log(M/N)
nlogM=logM^n

2007-11-23 08:56:49 · answer #4 · answered by athul e 2 · 0⤊ 0⤋