The answer should come out in brackets, help please!!??
2007-11-22 20:21:19 · 8 answers · asked by Info team 2 in Science & Mathematics ➔ Mathematics
3x^2-4x-5=0
delta=4^2-4*3*(-5)=8+60=68
=>sqrt(delta)=sqrt(68)=2sqrt(17)
=>x1=[4-2srqt(17)]/6=[2-sqrt(17)]/3
and x2=[4+2srqt(17)]/6=[2+sqrt(17)]/3
2007-11-22 20:41:59 · answer #1 · answered by kami 5 · 0⤊ 0⤋
3x^2 - 4x -5 =0?
4 plus or minus the square root of 76 over 6.
2007-11-23 04:30:50 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Here a = 3 ,b = - 4, c= -5
Discriminant = b^2-4ac
= (-4)^2 - 4 * 3 * -5
= 76
x= (-b+squareroot(discriminant))/(2a) or x=(-b-squareroot
(discriminant))/(2a)
ie; x = (4 + squareroot(76))/(2*3) or x = (4 - squareroot(76))/
(2*3)
x =2.119 or -0.78
2007-11-23 04:36:12 · answer #3 · answered by Anonymous · 0⤊ 0⤋
x = [ 4 ± â(16 + 60) ] / 6
x = [4 ± â(76)] / 6
x = [4 ± 2â(19)] / 6
x = (1/3) [ 2 ± â(19) ] gives exact answers.
Any other answers are an approximation.
2007-11-23 05:27:05 · answer #4 · answered by Como 7 · 0⤊ 1⤋
this is a quadratic equation of the form ax^2 + bx + c = 0.
general formula for this is : x= (-b + (b^2-4ac)^0.5)/(2a).
x= (-b - (b^2-4ac)^0.5)/(2a).
here a=3, b=-4,c=-5;
therefore... x= (4+76^0.5)/6 and (4-76^0.5)/6.
2007-11-23 04:32:42 · answer #5 · answered by Bharghava 3 · 0⤊ 0⤋
1st: x= ((19)^1/2 +2)/3
2nd: x= (2-(19)^1/2 )/3
2007-11-23 06:02:37 · answer #6 · answered by Brajendra 3 · 0⤊ 0⤋
x = -0.78 and 2.12. Gotta use the quadratic here
2007-11-23 04:27:59 · answer #7 · answered by Anonymous · 0⤊ 0⤋
(4+(76^0.5))/6 and (4-(76^0.5))/6
2007-11-23 04:26:44 · answer #8 · answered by Gauthaman MS 2 · 0⤊ 0⤋