2007-11-22 19:57:34 · 15 answers · asked by suri 1 in Science & Mathematics ➔ Mathematics
Not enough information is available. It has not been mentioned that there is grass in the square plot or there is grass outside the square plot.
Facts that can be determined with the information provided are:
The area of the square plot which the goat can cover is one fourth of the area the goat can totally cover.
Area that the goat can cover = π x 7² m²
Area that the goat can cover in the square plot = (1/4) x π x 7² m²
2007-11-23 13:23:42 · answer #1 · answered by Mathavan M 2 · 0⤊ 0⤋
Goat can graze an area = Quarter of the circle of radius 7m
Thus area = 1/4 [ Pi.7^2 ]
If Pi = 22/7, then this area = 1/4 [ (22/7) .7^2 ] = 38.5 m^2
2007-11-23 04:28:11 · answer #2 · answered by Pramod Kumar 7 · 0⤊ 0⤋
It is like 1/4 the area of a circle. I am assuming it can only graze inside the square. The radius of the circle is the 7 meter rope. Area of a circle pi r^2 = pi 49 = 483.595 sq. meters. Area /4 = 120.898 sq. meters. The 12 meters says it is inside the square.
2016-04-05 04:31:50 · answer #3 · answered by Anonymous · 0⤊ 0⤋
The area in which she can not graze
= area of circle/4
= pir^2/4 = (22/7) × 7 × 7/4 = 154/4 m^2 = 38.5 m^2
Area in which she can not grazw =
Area of square – area of circle/4
= 12 × 12 – 38.5 = 144 – 38.5 = 105.5 m^2 only.
2007-11-22 21:40:01 · answer #4 · answered by Pranil 7 · 0⤊ 0⤋
presuming no area is occupied by the peg it is tied to in the plot. and also presuming the
There is no length lost in the looping around the neck of the goat .
The goat is tied at the neck and not at the leg
the neck has negligible dimension so as to levae the effective length 7 m intact.
Considering the assumption it could be said MINIMUM area it can graze is 38.5 sq m.
If the goad is tied at the rear leg it could be about 72 sq m
2007-11-22 20:31:57 · answer #5 · answered by Anonymous · 0⤊ 0⤋
Well, the answer is 38.5 square metres (pi * 7*7 / 4, actually closer to 38.4834), as has been pointed out.
What has not been pointed out is that the size of the plot is irrelevant, providing it is more than 7m square.
.
2007-11-22 20:20:27 · answer #6 · answered by tsr21 6 · 2⤊ 0⤋
That would just be one quarter of a circle of radius 7
pi * 7^2 * (1/4)
=49*pi / 4
=38.5 m^2
2007-11-22 20:03:26 · answer #7 · answered by Anonymous · 0⤊ 0⤋
A = (1/4) x π x 7² m²
A = (1/4) x 22/7 x 49 m²
A = 38.5 m²
2007-11-23 02:31:36 · answer #8 · answered by Como 7 · 0⤊ 1⤋
Find the area of the circle with 7m radius then divite it by 4 then you have the answer.
2007-11-25 21:04:42 · answer #9 · answered by tmi_shadows 2 · 0⤊ 0⤋
You may apply the formula 22/7x 7 x 7 = 22x 7=154 Sq.Mts.
2007-11-22 20:27:06 · answer #10 · answered by chandrasekharam b 7 · 0⤊ 1⤋