APPLYING TRIGONMETRY-A steel ramp is 12 meters long and rises 3 metres.?

Question

What angle does the ramp make with the ground?

Answer 1

the angle = arcsin(3/12) = 14.48 degrees, since it is the opposite side over the hypotenuse.

Answer 2

Pool is a trapezoidal prism finished quantity: V = 12 * 6 *(a million + 3)/2 = 144m³ till the water is two meters deep (on the deep end) that is merely filling a triangular prism Water at the instant in pool: The intensity of the pool changes at a cost of 1m for each 6m so whilst there's a million m of water in the deep end the quantity is: V = 6 * 6 * a million * a million/2 = 18m² 18/a hundred and forty four * a hundred% = 12.5% b) dV/dt = 4m³/min permit d = intensity of water at deep end width of water is 6d width of pool is 6 triangular prism V = a million/2 * 6d * d * 6 = 18d² dV/dt = 36d dd/dt 4 = 36(a million) dd/dt dd/dt = 4/36 = a million/9 Water is turning out to be a million/9 of a meter consistent with minute

Answer 3

14 degrees

Inverse Tangent(Opposite/Adjacent) = Angle
= Inverse Tangent (3/12)
= Inverse Tangest (0.25)
= 14 degrees

Answer 4

Are you trying to have us do your homework? :) Something I've always remembered is SOH CAH TOA. Which means Sin = Opposite/Hypotenuse, Cosine = Adjacent/Hypotenuse and Tangent = Opposite/Adjacent. That and the Pythagorean theorem is pretty much all the Trigonometry you'll ever need.

Answer 5

Let angle = θ
sin θ = 3/12
θ = 14.5 °

Answer 6

sinx = 3/12
Therefore x = arcsin(3/12)