A 10.0-L flask contains 0.400 mole of H2, 0.300 mole of He and 0.500 mole of Ne @ 35*C.?

Question

What is partial pressure of Ne Thanks and God Bless

Answer 1

First, determine the total pressure on the system, then calculate the part from the Ne.

PV = nRT so P = nRT/V

P = 1.200mole x 0.08206latm/mol K (273 + 35K/10.0L = 3.03atm

The partial pressure of the Ne is proportional to the mole fraction:

[0.500/(0.300 + 0.400 + 0.500)] x 3.03 atm =

1.26 atm