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In regards to the mono-chlorination of 2,2-dimethylbutane

2007-11-22 14:16:37 · 1 answers · asked by Anonymous in Science & Mathematics Chemistry

1 answers

The substrate is (CH3)3C-CH2CH3. So you put one Cl on any of the first CH3's, and that's one isomer. Put one on the CH, and that's the second isomer. Finally, put a Cl on the end CH3, and that's the third isomer.

2007-11-22 14:32:05 · answer #1 · answered by steve_geo1 7 · 0 0

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