Aspirin (C9 H8 O4) can be made in the lab by reacting salicylic acid (C7 H6 O3) with acteyl chloride?

Question

Acetyl chloride (C2 H3 CLO). What mass of aspirin is produced by the reaction of 40.0g of Salicylic acid and 30.0g of acteyl chloride
C7 H6 O3 + C2 H3 CLO ----> C9 H8 O4 + HCL

Answer 1

First determine the moles of each reactant to find the limiting reagent; this will tell the quantity of product formed.

Salicylic acid is: (12 x 7) + (6 x 1) + (16 x 3) = 138g/mole
Acetyl chloride is: (12 x 2) + (3 x 1) + 16 + 35.45 = 78.45g/mole
Aspirin is: (12 x 9) + (8 x 1) + (16 x 4) = 180g/mole

So: 40g/138g/mole = 0.29mole
and: 30g/78.45g/mol = 0.38mole

The two materials react in a 1 to 1 ratio, so salicylic acid is the limiting reagent; you will get 0.29mole of asprin or:

0.29mole x 180g/mole = 52grams

Answer 2

Calculate moles of each and every reactant. 50.0 g C7H6O3 x (a million mole C7H6O3 / 138 g C7H6O3) = 0.362 moles 40.0 g C2H3ClO x (a million mole C2H3ClO / seventy 8.5 g C2H3ClO) = 0.510 moles because of the fact the balanced equation tells us that the two reactants are in a a million:a million ratio, then C7H6O3 is the proscribing reagent on account that there are fewer moles of it than C2H3ClO. 0.362 moles C7H6O3 x (a million mole C9H8O4 / a million mole C7H6O3) x (one hundred eighty g C9H8O4 / a million mole C9H8O4) = sixty 5.2 g aspirin (C9H8O4)