Maths Quadratics URGENT??

Question

1.(a)For the quadratic y = x² - 6x – 27 ,( without using your graphics calculator)
(i) factorise by inspection and find the x intercepts
(ii )find the y intercept
(iii)find the coordinates of the vertex
(iv)find the minimum value

(b)For the quadratic use your graphics calculator to find, (correct to 2 dp) [Using X min =-6.3 X max 6.3 scale = 1, Y min = - 6.2 Y max = 3.1 scale= 1]
(i)the x intercepts
(ii)the y intercept
(iii)the coordinates of the vertex
(iv)the minimum value
2.
(i)Simplify leaving your answer in surd form with an integer denominator.
(ii)Simplify leaving your answer in the form .
(iii)Simplify 2(5 - 3i) - 3(7 -4i) into the form a + bi
(iv)Simplify ( 2 – 3i) ( 5 + 2i ) into the form a + bi

3.Use the discriminant to find how many zeros, and if real or imaginary, for the quadratic y = 4 -5x +2x²

4.Solve, using the quadratic formula, the exact solution(s) to x² - 6x + 13 = 0

PLEASE HELP ASAP!

Answer 1

1. (a) y = x² - 6x – 27
(i) (x + 3)(x - 9)
(ii) y(0) = -27
(iii) y = x² - 6x + 3² - 9 - 27
y = (x - 3)² - 36
Vertex @ (3, - 36)
(iv) min = - 36

Answer 2

1a. Just factor the damn thing
(x+3)(x-9)
The x-intercepts are -3 and 9
2. -27 looking at the equation
3. 3, -36
5. Y=-36