2*sqrt(y/2) = sqrt(2y) ; why?

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I'm forgetting some algebra rules; why is this true?

2007-11-22 09:57:18 · 3 answers · asked by RogerDodger 1 in Science & Mathematics ➔ Mathematics

The inital 2 is out of the sqrt, and we know that 2 is the sqrt of 4. That means we can simplify it to sqrt(y/2*4). This therfore becomes sqrt(2y)

2007-11-22 10:04:29 · answer #1 · answered by Anonymous · 0⤊ 0⤋

You multiply it by 2 then divide it by 2. The value is the same. You just restated it.

2007-11-22 10:39:09 · answer #2 · answered by Nomadd 7 · 0⤊ 0⤋

2(y/2)^1/2 = 2^(1 -- 1/2)*y^(1/2) = 2^(1/2)*y^(1/2) = sqrt2y

2007-11-22 10:04:49 · answer #3 · answered by sv 7 · 0⤊ 0⤋