When solving for "x" in this equation:
log_2(x) + log_2 (5)=3
I got x=1.6 or 8/5
3^2x=27^2x-3
I got x=9/4
I have no idea if these are right, I'm guessing here.
Thanks.
2007-11-22 09:57:03 · 4 answers · asked by ms_lotr_freak 3 in Science & Mathematics ➔ Mathematics
Logs are base-2
log(x) + log(5) = 3
log(5x) = 3
5x = 2^3
5x = 8
x = 8/5
3^(2x) = 27^(2x-3)
27 = 3^3
3^(2x) = (3^3)^(2x-3)
3^(2x) = 3^(6x-9)
2x = 6x-9
4x = 9
x = 9/4
2007-11-22 10:00:25 · answer #1 · answered by gudspeling 7 · 1⤊ 0⤋
7
2007-11-22 09:58:52 · answer #2 · answered by Anonymous · 0⤊ 2⤋
Emails, I surely have the Yahoo toolbar on the proper of my reveal so i am going to ensure if I surely have any new messages on condition that i very last logged onto domicile windows. If I surely haven't any new messages I click on the solutions image instead.
2016-10-24 22:30:20 · answer #3 · answered by ? 4 · 0⤊ 0⤋
http://answers.yahoo.com/question/index?qid=20071120093610AAaG2HI&r=w
2007-11-22 10:04:46 · answer #4 · answered by ღOMGღ 7 · 0⤊ 2⤋