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How do I write x+1>-2 and x+1<6
without using and? Could you please explain it? I don't get how to write it without and.

2007-11-22 08:06:42 · 6 answers · asked by Anonymous in Science & Mathematics Mathematics

how do you slove
-2

2007-11-22 08:16:40 · update #1

6 answers

rewrite the inequalities so they express the relations in terms of x by itself:
x + 1 > -2  ⇒  x > -3
x + 1 < 6  ⇒  x < 5

Now get the inequalities pointed in the same direction:
x > -3  ⇒  -3 < x
 x < 5  no change needed

and combine them:
-3 < x and x < 5 
∴ -3 < x < 5 

This could also be written in decreasing order (5 > x > -3), but the convention is to use increasing order  (-3 < x < 5) because that's the way the number line is oriented.

2007-11-22 08:14:35 · answer #1 · answered by DWRead 7 · 0 0

x+1 > -2 so -2 < x+1 and x+1 < 6.
Then : -2 < x+1 < 6

2007-11-22 08:09:10 · answer #2 · answered by antone_fo 4 · 0 0

First, get the x's by themselves in each. Subtracting 1 from both sides of the first, you have x>-3. The other you'll have x<5. So, then, organize this so all your inequalities face the same way. You have -35, because if you wrote it 5

2007-11-22 08:12:36 · answer #3 · answered by Chris S 2 · 0 0

u write it like this 6>x+1>-2

all you do is put the common side of each equation and according to the facts you fill it in. I put x+1 in the middle and 6 on one side while 2 is on the other. This way it is one equation and both facts are true

2007-11-22 08:10:56 · answer #4 · answered by broken_glass_101 3 · 1 0

Lol I just did this in math a week or so ago i really can't remember.. errrrrrr

I'll look wait lol.

x > -1 -2
x> -3

x> -1 +6
x>5

Collect the x's on one side, and then the numbers on the other

Always collect the x's where there are most x's to start with

so if it was

2x < x + 1

Put the x on the 2x side

2x-x<1
x<1

2007-11-22 08:10:39 · answer #5 · answered by Anonymous · 0 1

-2 < x+1 (put the lowest number 1st)
and
x+1 < 6 (put the highest number last)
-2 < x+1 < 6 (which puts the x-expression in the middle)

2007-11-22 08:11:59 · answer #6 · answered by Philo 7 · 1 0

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