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The question from the text:

Are the following substances electrolytes or non-electrolytes? Write equations to illustrate your answers.

I'm unsure about a couple of them. I'd like to just be sure I'm going about this correctly:

substance: C2H5OH(l) in water
My equation: C2H5OH(l) --[in water]--> C2H5OH(aq); non-electrolyte.

substance: O2(g)
My equation: O2(g)--[inwater]-->O2(g); non-electrolyte

2007-11-22 08:01:58 · 3 answers · asked by glurpy 7 in Science & Mathematics Chemistry

3 answers

Dissolving process can be in two ways;
(1) Molecular dissolving : Dissolving of covalent compounds which does not produce ions to carry the electric charge, therefore the solution is nonelectrolyte.
(2) Ionic dissolving: Dissolving of ionic compounds which produces ions to carry the electric charge, therefore the solution is electrolyte.

Your both substances are molecular substances (composed of only nonmetals) therefore their solutions are non electrolytes.

The subscripts identifying the states are sufficent to express the process, therefore no need to add water.
For example;
C2H5OH (l) -----------> C2H5OH(aq)
denotes that liquid ethyl alcohol dissolves in water to form an aqueous solution.
O2(g) -------> O2(aq) represents the dissolved oxygen in water.
NaCl(s) ------> NaCl(aq) Dissolving of table salt in water
NaCl(s) ------> NaCl(l) Melting of table salt by the action of heat.
NaCl(s) -------> Na^+(aq) + Cl^-(aq) ionization of NaCl in water.
NaCl(s) -------> Na^+(l) + Cl^-(l) ionization of NaCl in molten form

Your answers are correct, only change O2(g) to O2(aq) in the product side.

One more remark for my explanation: I used an expression above as " molecular substances (composed of only nonmetals)" . Of course there are some exceptions.
NH4NO3 (ammonium nitrate) is composed of nonmetals it is an ionic salt. It dissolves;

NH4NO3(s) --------> NH4^+(aq) + NO3^-(aq)
forming ammonium and nitrate ions (electrolyte).

2007-11-22 21:42:25 · answer #1 · answered by Guray T 6 · 0 0

2Na(s) + 2H2O(l) ? 2NaOH(aq) + H2(g) Na oxidation extensive sort = 0 H20 oxidation numbers: O = -2 H = +a million NaOH oxidation numbers = Na = +a million O = -2 H = +a million H2 oxidation extensive sort = 0 because of the fact the oxidation numbers replace, that's a redox reaction. Na^0 ---> Na^+a million subsequently, Na has lost elections, and has grow to be oxidized, making it the reducing agent. H^+a million ---> H^0 subsequently, H has won elections, and has grow to be decreased, making it the oxidizing agent. remember this little asserting: LEO the lion is going GER. L = dropping E= Elections O =Oxidized meaning, while an atom loses elections, that's oxidized. G = Gaining E = Electrons R = decreased. meaning, while an atom helpful properties elections, that's oxidized.

2016-12-16 16:14:11 · answer #2 · answered by ? 4 · 0 0

Correct.

It's only an electrolyte in water if it makes ions.

2007-11-22 08:05:27 · answer #3 · answered by Facts Matter 7 · 0 0

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