Please explain
2007-11-22 06:27:41 · 12 answers · asked by Bobby S 3 in Science & Mathematics ➔ Mathematics
x + (x + 1) + (x + 2) + ( x + 3) =2
4x + 6 =2
x = -1
therefore -1 is the smallest integer
2007-11-22 06:31:10 · answer #1 · answered by suey 2 · 2⤊ 0⤋
Let the first integer be x then, the second number will be x+1 third will be x+2 fourth will be x+3, since the four integers are consecutive..... now, the sum of four integers is 9 less than 5times the first integer... i.e. sum of integers = 5 times of first - 9 => x + (x+1) + (x+2) + (x+3) = 5(x) - 9 => 4(x) + 6 = 5(x) - 9 on solving, it gives x = 15 so the integers are 15, 16, 17 and 18 hope its clear..:)
2016-05-25 00:54:39 · answer #2 · answered by ? 3 · 0⤊ 0⤋
Four consecutive integers are -1 , 0 , 1 , 2 .
Sum = -1 + 0 + 1 + 2 = 2.
Smallest of these four integer is -1.
2007-11-22 06:32:47 · answer #3 · answered by Anonymous · 1⤊ 1⤋
-1 that is
-1+ 0 + 1 + 2 = 2
2007-11-22 06:32:52 · answer #4 · answered by maya4f 2 · 1⤊ 1⤋
smallest is (2 -- 6)/4 = -- 1
others are 0, 1, 2
explaination :
sum of n consecutive integers,
s = n*smallest + (1 + 2 + ...+ n --1) whence
smallest integer = [s -- (1+2+3+ ... + n -- 1)]/n
2007-11-22 06:54:50 · answer #5 · answered by sv 7 · 0⤊ 2⤋
-1, 0, +1, +2 = 2
2007-11-22 06:32:25 · answer #6 · answered by brainyandy 6 · 1⤊ 0⤋
x + (x + 1) + (x + 2) + (x + 3) = 2
4x + 6 = 2
4x = - 4
x = - 1
- 1 is smallest integer.
2007-11-22 06:39:06 · answer #7 · answered by Como 7 · 2⤊ 1⤋
Ok this is easy.
n+(n+1)+(n+2)+(n+3) = 2
4n + 6 = 2
4n = -4
n = -1
The smallest of the four integers is -1
2007-11-22 06:33:23 · answer #8 · answered by Anonymous · 2⤊ 1⤋
(x+0)+(x+1)+(x+2)+(x+3) = 2
4x+6= 2
4x+6(-6) =2 -(6)
4x = -4
x = -1
-1 + 0 +1 + 2 = 2
The smallest is: (-1)
2007-11-22 07:34:42 · answer #9 · answered by Eduardo (lalo) Leal 2 · 0⤊ 2⤋
x+(x+1)+(x+2)+(x+3)=2
4x+6=2
4x=2-6
4x=-4
x=-4/4
x=-1
so smallest of these 4 integers is -1
2007-11-22 06:54:37 · answer #10 · answered by Anonymous · 0⤊ 2⤋