elevator problem - physics?

Question

i have a video recording of a person's weight as it changes while the elevator accelerates, comes to a constant speed, and decelerates to a stand-still.

how do i figure out the height the elevator traveled to? equations would be best, as i will put in my own data. THANKS!

Answer 1

This is a three-part problem.

1. Initial acceleration

Use the weight to find the acceleration of the elevator during this time. The distance traveled is

h = 1/2 a t^2

and the final velocity is

v = a t

2. Constant speed

The distance traveled is simply v t where v is the final velocity from part 1.

3. Decelleration

Just like part 1: find the acceleration, then calculate the distance traveled during that time.

Answer 2

when a person travels up in the elevator there is a force due to gravity plus the acceleration of the elevator. When the elevator goes down there is a gravity force pulling down minus the elevator force.

so....going up is
(gravity +elevatorAcceleration)*mass

going down is
(gravity - elevatorAcceleration)*mass

Answer 3

Let's say you did figure that out, what would it buy you? Spend your time learning an occupation instead..