physics word problem . HELP PLEASE !!!!!?

Question

A 0.220 kg block on a vertical spring with spring constant of 4.20*10^3 N/m is pushed downward, compressing the spring 0.053 m. When released, the block leaves the spring and travels upward vertically. How high does it rise above the point of release?

Answer 1

Force = spring constant * extension

Energy stored at extension 0.053 m
=1/2 * force * extension
=1/2 * spring constant * extension^2
=1/2 (4.2*10^3)(0.053)^2=5.8989 J.

Elastic potential = Gravitational potential energy
5.8989 = mass X gravity acceleration X height
5.8989 = 0.220 X 9.8 X H
H=2.736 m
Height approx. = 2.74m

Answer 2

The energy of the spring Ps is converted to potential energy Pe of the block
Ps=Pe

Ps= 0.5 k x^2
k- spring constant
x - distance spring was compressed

Pe= mgh
m - mass of the object
g - acceleration due to gravity
h - height we seek

since mgh =0.5 k x^2
then
h= 0.5 k x^2 / mg

h= 0.5 x 4.20 E+3 x (0.053)^2 / (0.220 x 9.81)
h=2.7 m (use only two significant figures since only 2 are given in measured values)