What is the gravitational potential energy associated with the ball relative to the ceiling?

Question

A 1.9 kg ball is attached to a ceiling by a string. The distance from the ceiling to the center of the ball is 1.19 m, and the height of the room is 3.00 m.

Answer 1

-22.1578

Answer 2

Depends.

If you are measuring the PE to the floor of the room, then what the first answer gave is correct. PE = mgh; where m is the ball's mass, g = 9.81 m/sec^2, and h = H -s; where H = 3 m is the ceiling height and s = 1.19 m is the length of string.

But, and this is a big BUT, if your room is on the tenth floor of a building and you're measuring the PE wrt the ground outside, then PE = mgh; where h = 10H - s; where 10H is the height above ground for the ceiling of the room on the tenth floor.

I realize h = H - s most likely for your problem. But I bring up the other possibility to illustrate the physics. The reason that ball has potential energy is because work WE = fh was put into that ball to lift it against the force (f = mg) of gravity to the height h.

So it follows, PE = mgh = WE and what we do when lifting the ball to h is convert that work into potential energy. And this results from the conservation of energy law. The WE is conserved as PE. As the work going into raising the ball to the tenth floor is WE = mg(10H - s), that has to be the potential energy as well wrt to the ground at the foot of the building.

Answer 3

The answer should be negative because "gravitational potential energy" is the potential energy caused by gravity, which goes downward away from the ceiling. Also, most high school physics use 9.8 m/s^2 instead of 10 m/s^2, because 9.8 is more accurate.

Potential Energy = mgh = (1.9 kg)(9.8 m/s^2)(-1.19 m) = -22.1578 J

Answer 4

Gravitational Potential energy = Mass X Gravity accleration X height

Mass= 1.9
GRavity accleration = 10
Height = 3-1.19 =1.81

G.P.E= 1.9*10*1.81
=34.39 J.

Answer 5

Gravitational skill capacity because of charm of earth is given via the equation (PE) = (GMm) / (R+h) G=conventional gravitational costant;M=Mass of the earth;m=mass of the ball ;R=radius of earth ;h = height of the ball from the suface of the earth. G=6.sixty seven*10^-11; M=7.4*10^22Kg R= one million.7*10^6m h=3-one million=2m; m=2.00Kg ==>Gravitational skill capacity (PE) = (6.sixty seven*10^ -11 * 7.4*10^22 * 2)/one million.7*10^6 (his very small it quite is neglected). (PE) = (ninety 8.716 *10^11)/one million.7 *10^6 (PE) = fifty 8.07 *10^5 j In all the three circumstances the (PE) would be comparable,because of fact the gravitational PE is calculated with appreciate to that is height from floor of earth. This h cost is comparable in all the three circumstances,subsequently PE will additionally be comparable.