cbroot(27/64) = cbroot(27) / cbroot(64) = 3 / 4
2007-11-22 00:10:17
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answer #1
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answered by GusBsAs 6
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Well think of 27 over 64 as two separate number. Now try looking for the cube root of both. Cube root of 27 would be 3 times 3 times 3, meaning your numerator would be 3. Now for 64, the cube root of that would be 4 times 4 times 4 meaning your denominator will be 4. so final answer is 3/4
2007-11-22 00:15:14
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answer #2
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answered by Shatteredj 3
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Cubed Root Of 27
2016-10-16 03:43:08
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answer #3
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answered by Anonymous
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it is equal to cube root of 27 divided by cube root of 64.
of 27 = 3 since 3*3*3 = 27 and of 64 = 4 since 4*4*4 = 64.
SO answer is 3/4 = 0.75
2007-11-22 00:17:50
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answer #4
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answered by dren 3
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³√27/64 =³√(3³ /4 ³) = 3/4
2007-11-22 00:13:26
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answer #5
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answered by mbdwy 5
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cube root of 27/64
= [ 27/64 ]^1/3
= [ 3^3 / 4^3 ]^1/3
= [(3/4)^3]^1/3
= [ 3/4 ]^(3 multiplied by 1/3)
= [ 3/4 ]^1
= 3/4 ....... Answer
2007-11-22 00:51:33
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answer #6
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answered by Pramod Kumar 7
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Cube root of upper side is 3 because 3x3x3= 27
and cube root of denominator es 4 because 4x4x4=64
so cubic root(27/64)=3/4
regards.
2007-11-22 00:11:27
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answer #7
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answered by el p. ch. 4
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(27/64)^(1/3) = 3 / 4
Note
3 x 3 x 3 = 27
4 x 4 x 4 = 64
2007-11-22 01:24:03
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answer #8
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answered by Como 7
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cube root of 27 (3) is divided by cube root of 64 (4).
The result is 3/4 -- (.75)
2007-11-22 00:45:29
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answer #9
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answered by x j b 1
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27/64 = ?
the cube root of 27 is 3
the cube root of 64 is 4
if you want to solve further,
3 divided by 4 will give you 0.75
2007-11-22 01:39:03
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answer #10
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answered by SIMONE 5
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