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CH3OH --> CO + 2H2.

For a given sample of CH3OH, the enthalpy change on reaction is 17.5kJ.

2007-11-21 21:01:45 · 1 answers · asked by hobiesailor07 1 in Science & Mathematics Chemistry

1 answers

impossible to tell, unless you tell us how much starting material you had.

If you know g CH3OH, it's just the usual unit conversion:

g CH3OH

x 1 mol CH3OH /(formula mass CH3 OH)

x 2 mol H2/1 mol CH3OH (from reaction equation)

x formula mass (g) H2/mol H2

If you have been told, or have been given enough information to work out, the enthalpy change of the reaction, you can use

17.5 kJ = enthalpy change per mole x number of moles

2007-11-22 05:51:27 · answer #1 · answered by Facts Matter 7 · 0 0

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