Gary has $4.40 in nickels and dimes. He has 10 more nickels than dimes.howmany o'each kind o'coin does he have

Answer 1

Let N be the number of nickels
Let D be the number of dimes

Number of nickels is 10 more than the number dimes.
N = D + 10

Value of the coins is $4.40 (440 cents)
5N + 10D = 440

Substitute the value of N into the second equation:
5(D + 10) + 10D = 440
5D + 50 + 10D = 440
15D = 440 - 50
15D = 390
D = 26

N = D + 10
N = 26 + 10
N = 36

26 dimes ($2.60)
36 nickels ($1.80)

Answer 2

This question can be easily answered by first defining a few variables and setting up a basic equation.

First of all, dimes are worth 10 cents or $0.1. Nickels are worth 5 cents or $0.05.

From the problem, we know that there are 10 more nickels than dimes. So,

x= number of dimes
x+10= number of nickels

The equation is then:

0.1x+0.05(x+10)=4.40

Or you can convert $4.40 to 440 cents and set the equation up like this:

10x+5(x+10)=440

Either way the answer is the same.

So,

10x+5(x+10)=440 (multiply 5 to what's in the brackets)
10x+5x+50=440
15x+50=440
15x=440-50=390
15x=390
x=390/15=26
x=26

So, x=26 and you have 26 dimes. x+10=nickels, so 36 nickels. You can substitute this value in to check your results.

Answer 3

Of the $4.40 total, $0.50 is made up of ten nickels. The remainder ($3.90) is made up of an equal number of nickels and dimes.

Putting it another way, the remaining $3.90 is made up of a number of pairs of nickels and dimes. Since each nickel and dime pair totals $0.15, dividing $3.90 by $0.15 gives the number of nickel/dime pairs: $3.90 / $0.15 = 26.

This means that there are 26 dimes (= $2.60) and 26 +10 = 36 nickels (= $1.80) for a total of $4.40.

Answer 4

26 dimes
36 nickels