How many base digits does the # 9^9^9 have when written base in nine?

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How many base digits does the # 9^9^9 have when written base in nine?

2007-11-21 19:12:43 · 3 answers · asked by carlaann12 1 in Science & Mathematics ➔ Mathematics

3 answers

In base 9, 9^n will consist of a 1 followed by n zeros, and will therefore have n+1 digits. Therefore, 9^9^9 has 9^9 + 1 digits, which is 387,420,490.

2007-11-21 20:29:50 · answer #1 · answered by Pascal 7 · 0⤊ 1⤋

9^9^9
= 9^81
9^9^9 has 81+1 = 82 digits in base nine.
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Ideas: Think about 10^81. How many digits does it have?

2007-11-21 19:18:12 · answer #2 · answered by sahsjing 7 · 0⤊ 4⤋

only one. just the nine. hehe

2007-11-21 19:31:17 · answer #3 · answered by rnygelle87 2 · 0⤊ 2⤋